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H2S , a toxic gas with rotten egg like s...

`H_2S` , a toxic gas with rotten egg like smell, is used for the qualitative analysis. If the solubility of `H_2S` in water at STP is 0.195 m, calculate Henry's law constant

Text Solution

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Solubility of `H_2S` gas = 0.195 m i.e., 0.195 mole in 1 kg of the solvent (water)
1 kg of the solvent (water) = 1000 g = 1000/18g = 55.55 moles
` therefore ` Mole fraction of `H_2S` gas in the solution (x) = `(0.195)/(0.195 + 55.55) = 0.0035`
Pressure at STP = 0.987 bar
Applying Henry.s law,
`p_(H_2S) = K_H xx x_(H_2S) " or " K_H = (p_(H_2S))/(x_(H_2S)) = (0.987 bar)/(0.0035) = 282 bar `
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H_(2)S , a toxic gas with rotten egg like smell, is used for the qualitative analysis.If the solubility of H_(2)S in water at STP is 0.195 m , calculate Henry's law constant.

H_(2)S , a toxis gas with rotten egg like small, is used for qualitative analysis. If the solubility of H_(2)S in water at STP is 0.195 m, calculate Henry's law constant.

Knowledge Check

  • H_(2)S gas is used in qualitative analysis of inorganic cations. Its solubility in water at STP is 0.195 mol Kg^(-1) .Thus, Henry's law constant (in atm mola l^(-1) )for H_(2)S is

    A
    `2.628xx10^(-4)`
    B
    `5.128`
    C
    `0.185`
    D
    `3.826xx10^(3)`
  • H_2 S is used for precipitation of cations of

    A
    2nd group
    B
    2nd and 4th group
    C
    3rd and 4th group
    D
    4th and 5th group
  • When SO_2 is passed through a solution of H_2 S in water :

    A
    Sulphuric acid is formed
    B
    A clear solution is formed
    C
    Sulphur acid is precipitated
    D
    No change is observed
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