`H_2S` , a toxic gas with rotten egg like smell, is used for the qualitative analysis. If the solubility of `H_2S` in water at STP is 0.195 m, calculate Henry's law constant
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Solubility of `H_2S` gas = 0.195 m i.e., 0.195 mole in 1 kg of the solvent (water) 1 kg of the solvent (water) = 1000 g = 1000/18g = 55.55 moles ` therefore ` Mole fraction of `H_2S` gas in the solution (x) = `(0.195)/(0.195 + 55.55) = 0.0035` Pressure at STP = 0.987 bar Applying Henry.s law, `p_(H_2S) = K_H xx x_(H_2S) " or " K_H = (p_(H_2S))/(x_(H_2S)) = (0.987 bar)/(0.0035) = 282 bar `
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