Calculate the freezing point of a solution containing 60 g of glucose (Molar mass = `180 g "mol"^(-1)` )

Explanation

Apply the formula
` Delta T_f = (K_f xx w_2 xx 1000)/(M_2 xx w_1)`
substituting the values in the above equation , we have
` Delta T_f = (1.86 K kg "mol"^(-1) xx 60g xx 1000 g kg^(-1))/(180 g "mol"^(-1) xx 250 g)`
`Delta T_f = (1.86 xx 60 xx 1000)/(180 xx 250) = 2.48 K`
Freezing point of the solution ` = 273.15 K - 2.48 K = 270.67 K`