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Why a mixture of carbon disulphide and a...

Why a mixture of carbon disulphide and acetone shows positive deviation from Raoult's law ? What type of azeotrope is formed in this mixture ?

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A mixture of carbon disulphide and acetone shows positive deviation. This is because intermolecular forces of attraction between carbon disulphide and acetone are weaker than between pure components. A minimum boiling azeotrope is formed at a specific composition.
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Why a mixture of carbon disulphide and acetone shows positive deviation from Raoult's law ? What type of azeotrope is formed by this mixture?

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Knowledge Check

  • The mixture which shows positive deviation from Raoult's law is

    A
    ethanol + acetone
    B
    benzene + toluene
    C
    acetone + chloroform
    D
    chloroethane + bromoethane

  • Which of the following shows positive deviation from Raoult's law ?

    A
    `C_(6)H_(6) and C_(6)H_(5)CH_(3)`
    B
    `C_(^)H_(6) and C Cl_(4)`
    C
    `ChCl_(3) and C_(2)H_(3)OH`
    D
    `CHCl_(3) and CH_(3)COCH_(3)`

  • Which liquids pair shows a positive deviation from Raoult's law?

    A
    Acetone -chloroform
    B
    Benzene -methanol
    C
    Water-nitric acid
    D
    Water-hydrochloric acid

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    The mixture which shows positive deviation from Raoult's law is:

    The mixture which shows positive deviation from Raoult's law is :

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    Identify the mixture that shows positive deviations from Raoult's law

    A binary liqiud (AB) shows positive deviation from Raoult's law when

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