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In unit vector notation, find the net to...

In unit vector notation, find the net torque about the origin on a particle located at `(2.0m,-2.0m,-6.0m)` when the three forces `vecF_(1)=(6.0N)hatj,vecF_(2)=(1.0N)hati-(2.0N)hatj,andvecF_(3)=(4.0N)hati+(2.0N)hatj-(3.0N)k` act on the particle.

Text Solution

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To solve the problem, we need to find the net torque about the origin on a particle located at the position vector \( \vec{r} = (2.0 \, \text{m}, -2.0 \, \text{m}, -6.0 \, \text{m}) \) when three forces \( \vec{F}_1, \vec{F}_2, \) and \( \vec{F}_3 \) are acting on it. The torque \( \vec{\tau} \) is given by the cross product of the position vector \( \vec{r} \) and the net force vector \( \vec{F}_{\text{net}} \). ### Step 1: Define the position vector The position vector \( \vec{r} \) can be expressed in unit vector notation as: \[ \vec{r} = 2.0 \hat{i} - 2.0 \hat{j} - 6.0 \hat{k} \] ...
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In unit vector notation, find the torque about a point at coordinates (2.0 m, 1.0 m, 3.0 m) on a particle located at (3.0 m, 1.0 m, 2.0 m) when a force vecF=(1.0N)hati-(3.0N)hatk acts on the particle.

In unit vector notation, what is the torque about the origin on a particle located at coordinates (0, -4.0 m, 3.0 m) if that torque is due to (a) force vecF_(1) with components F_(1x)=2.0N,F_(1y)=F_(1z)=0 , and (b) force vecF_(2) with components F_(2x)=0,F_(2y)=2.0N,F_(2z)=4.0N ?

Knowledge Check

  • The resultant of the forces vecF_(1)=4hati-3hatj and vecF_(2)=6hati+8hatj is

    A
    `5sqrt(5)`
    B
    `10hati-5hatj`
    C
    125
    D
    `-2hati-3hatj`
  • The initail and final position vectors for a particle are respectively , ( - 3.0 m)hati + (2.0 m) hat j + (8.0 m ) hatk and (9.0 m)hati + (2.0 m )hatj + (- 8.0 m )hat k . The displacement of the particle is

    A
    `(6.0 m )hati + (4.0 m)hatj + (16.0 m ) hat k`
    B
    `(6.0 m ) hati `
    C
    `(12 .0 m)hati - (16.0 m ) hatk`
    D
    `(12.0 m)hat i `
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