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Write the Kp expression for PCl(5(g))hAr...

Write the Kp expression for `PCl_(5(g))hArr PCl_(3(g)) + Cl_(2(g))`

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1 mol PCl_(2)(g) is heated in a closed container of 2 litre capacity. If at equilibrium, the quantity of PCl_(5)(g) be 0.2 mol then calculate the value of equilibrium constant for the given reaction, PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) .

What will be the effect of addition of an inert gas in the following equilibrium at constant temperature and volume? PC l_(5)(g) hArr PCl_(3)(g) +Cl_(2)(g) .

Does the number of moles of reaction products increase, decrease of remain same when each of the following equilibria is subjected to a decrease in pressure by increasing the volume? PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)

Find out the value of K_(p)//K_(c) for the reaction PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) , at 298K, consider the unit of concentration is mol*L^(-1) and the unit of pressure is atm.

Which of the following relations are true for the reaction, PCl_(5)(g)toPCl_(3)(g)+Cl_(2)(g) -

The equilibrium established during thermal dissociation of PCl_(5)(g) in a closed vessel is as follows: PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) If the degree of dissociation of PCl_(5)(g) at equilibrium be 'x', then show that (1) 'x' is inversely proportional to the square root of the total pressure of reaction mixture at equilibrium and (2) 'x' increases with increase in volume of the system.

At 550 K, the value of equilibrium constant (K_(c)) is 0.08 for the given reaction: PCl_(5)hArrPCl_(3)(g)+Cl_(2)(g) occurring in a closed container. If the equilibrium concentration of PCl_(5)(g) and Cl_(2)(g) are 0.75 and 0.32 mol*L^(-1) respectively, then find the concentration of PCl_(3)(g) .

For the following endothermic reactions: PCl_(5)hArrPCl_(3)(g)+Cl_(2)(g) (a) At constant temperature, what will be the effect of pressure? (b) At constant volume, what will be the effect of addition of chlorine gas and nitrogen gas on the position of equilibrium?

At 473K, equilibrium constant K_(c) for decomposition of PCl_(5) is 8.3x10^(-3) . If decomposition is depicted as, PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g), DeltaH_(r)^(0)=124.0kJ*mol^(-1) Write an expression for the reaction.

At 25^(@)C , the thermal decomposition of PCl_5 occuring in a closed vessel of volume 1L gives rise to the equilibrium: PCl_5(g)hArr PCl_3(g)+Cl_2(g) . How many moles of PCl_5 is to be added so that the concentration of Cl_2(g) at equilibrium will be 0.1mol*L^(-1) ? [Given : K_p=1.78 (at 250^(@)C ]