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At 27^(@) C, H(2) is leaked through a ti...

At `27^(@) C`, `H_(2)` is leaked through a tiny hole into a vessel for 20 minutes Another unknown gas at the same T and P as that of `H_2` is leaked through the same hole for 20 minutes. After effusion of the gas, the mixture exerts a pressure of 6 atm. The `H_2` content of the mixture is 0.7 moles. If volume of the container is 3 litres what is the molecular weight of unknown gas ?

Answer

Step by step text solution for At 27^(@) C, H_(2) is leaked through a tiny hole into a vessel for 20 minutes Another unknown gas at the same T and P as that of H_2 is leaked through the same hole for 20 minutes. After effusion of the gas, the mixture exerts a pressure of 6 atm. The H_2 content of the mixture is 0.7 moles. If volume of the container is 3 litres what is the molecular weight of unknown gas ? by CHEMISTRY experts to help you in doubts & scoring excellent marks in Class 11 exams.

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Knowledge Check

  • The time taken for diffusion of CO_(2(g)) is twice than that of unknown gas of same volume under identical condition. Calculate the molecular weight of unknown gas. (C = 12, O = 16).

    A
    11 gm/mol
    B
    176 gm/mol
    C
    88 gm/mol
    D
    22 gm/mol

  • If pressure is P, temperature is T and gas constant is R. For an ideal gas, then the moles per litre of gas will be

    A
    `(RT)/(P)`
    B
    P R T
    C
    `(P)/(RT)`
    D
    `(PT)/(R )`

  • The rate constant of the reaction A to B is 0.6xx10^(-3) mole per second.If the concentration of A is 5 M ,then concentration of B after 20 minutes is :

    A
    0.36 M
    B
    0.72 M
    C
    1.08 M
    D
    3.60 M

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