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The equilibrium constant Kc for A((g))hA...

The equilibrium constant Kc for `A_((g))hArrB_((g))` is `2.5xx10^(-2)`. The rate constant of the forward reaction is `0.05" sec"^(-1)`. Calculate the rate constant of the reverse reaction.

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The correct Answer is:
`2.0" sec"^(-1)`
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Knowledge Check

  • The rate constant of a reaction depend on.

    A
    Temperature
    B
    Mass
    C
    Weight
    D
    time

  • The unit of rate constant for third order reaction is ..

    A
    `"mole"^(-3) "lit"^(3) s^(-1)`
    B
    `"mole"^(-2) "lit"^(-2)s^(-1)`
    C
    `"mole" "lit"^(-1) s^(-1)`
    D
    `"mole"^(-2) "lit"^(2) s^(-1)`

  • The value of rate constant of a pseudo first order reaction……

    A
    depends on the concentration of reactants present in samll amount
    B
    depends on the concentratin of reactants present in excess
    C
    is independent of the concentration of reactants
    D
    depends only on temperature.

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