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NCERT GUJARATI-DIFFERENTIAL EQUATIONS-EXERCISE - 9.6
- For each of the differential equations given inExercises 1 to 12, find...
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Play - (dy)/(dx) + (sec x)y = tan x (0 le x lt (pi)/(2))
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Play - cos^(2)x(dy)/(dx) + y = tan x (o le x le (pi)/(2))
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Play - x (dy)/(dx) + 2y = x^(2)log x
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Play - x log x(dy)/(dx) + y = (2)/(x)log x
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Play - (1 + x^(2))dy + 2xy dx = cot x dx (x ne 0)
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Play - x(dy)/(dx) + y - x + xy cot x = 0 (x ne 0)
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Play - (x + y )(dy)/(dx) = 1
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Play - y dx + (x - y^(2))dy = 0
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Play - (x + 3y^(2))(dy)/(dx) = y ( y >0).
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Play - (dy)/(dx) + 2 y tan x = sin x, y = 0 when x = (pi)/(3).
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Play - (1 + x^(2))(dy)/(dx) + 2xy = (1)/(1 + x^(2)), y = 0 when x= 1
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Play - (dy)/(dx) = 3y cot x = sin 2x, y = 2 when x = (pi)/(2)
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