Home
Class 12
PHYSICS
Choose the correct alternative from the ...

Choose the correct alternative from the clues given at the end of the each statement:
The size of the atom in Thomson’s model is .......... the atomic size in Rutherford’s model. (much greater than/no different from/much less than.)

Text Solution

Verified by Experts

No different from
Promotional Banner

Topper's Solved these Questions

  • ATOMS

    NCERT GUJARATI|Exercise ADDITIONAL EXERCISE|10 Videos

  • ATOMS

    NCERT GUJARATI|Exercise ADDITIONAL EXERCISE|10 Videos

  • ALTERNATING CURRENT

    NCERT GUJARATI|Exercise ADDITIONAL EXERCISES|19 Videos

  • CURRENT ELECTRICITY

    NCERT GUJARATI|Exercise ADDITIONAL EXERCISES|9 Videos

Similar Questions

Explore conceptually related problems

Choose the correct alternative from the clues given at the end of the each statement: A classical atom based on .......... is doomed to collapse. (Thomson’s model/ Rutherford’s model.)

Choose the correct alternative from the clues given at the end of the each statement: Thepositively charged part of the atom possesses most of the mass in .......... (Rutherford’s model/both the models.)

Choose the correct alternative from the clues given at the end of the each statement: In the ground state of .......... electrons are in stable equilibrium, while in .......... electrons always experience a net force. (Thomson’s model/ Rutherford’s model.)

Choose the correct alternative from the clues given at the end of the each statement: An atom has a nearly continuous mass distribution in a .......... but has a highly non-uniform mass distribution in .......... (Thomson’s model/ Rutherford’s model.)

Choose the correct alternative corresponding to the object distance 'u', image distance 'v' and the focal length 'F' of a converging lens from the following . The average speed of the image as the object moves with the uniform speed from distance (3F)/(4) to (F)/(2) is greater than the average speed of the image as the object moves with same speed from distance (F)/(2) "to" (F)/(4) The minimum distance between a real object and its real image in case of a converging lens is 4F where F is its focal length.

Choose the correct alternative: (a) Alloys of metals usually have (greater/less) resistivity than that of their constituent metals. (b) Alloys usually have much (lower/higher) temperature coefficients of resistance than pure metals. (c ) The resisitivity of the alloy manganin is nearly independent of/increases rapidly with increase of temperature. (d) The resistivity of a typical insulator (e.g., amber) is greater than that of a metal by a factor of the order of (10 ^(22) //10 ^(23)).

Answer the following questions, which help you understand the difference between Thomson’s model and Rutherford’s model better. (a) Is the average angle of deflection of a-particles by a thin gold foil predicted by Thomson’s model much less, about the same, or much greater than that predicted by Rutherford’s model?

In the Rutherford’s nuclear model of the atom, the nucleus (radius about 10^(–15) m) is analogous to the sun about which the electron move in orbit (radius ~~ 10^(–10) m) like the earth orbits around the sun. If the dimensions of the solar system had the same proportions as those of the atom, would the earth be closer to or farther away from the sun than actually it is? The radius of earth’s orbit is about 1.5 xx 10^(11) m. The radius of sun is taken as 7 xx 10^8 m .

A physical quantity is a phyical property of a phenomenon , body, or substance , that can be quantified by measurement. The magnitude of the components of a vector are to be considered dimensionally distinct. For example , rather than an undifferentiated length unit L, we may represent length in the x direction as L_(x) , and so forth. This requirement status ultimately from the requirement that each component of a physically meaningful equation (scaler or vector) must be dimensionally consistent . As as example , suppose we wish to calculate the drift S of a swimmer crossing a river flowing with velocity V_(x) and of widht D and he is swimming in direction perpendicular to the river flow with velocity V_(y) relation to river, assuming no use of directed lengths, the quantities of interest are then V_(x),V_(y) both dimensioned as (L)/(T) , S the drift and D width of river both having dimension L. with these four quantities, we may conclude tha the equation for the drift S may be written : S prop V_(x)^(a)V_(y)^(b)D^(c) Or dimensionally L=((L)/(T))^(a+b)xx(L)^(c) from which we may deduce that a+b+c=1 and a+b=0, which leaves one of these exponents undetermined. If, however, we use directed length dimensions, then V_(x) will be dimensioned as (L_(x))/(T), V_(y) as (L_(y))/(T), S as L_(x)" and " D as L_(y) . The dimensional equation becomes : L_(x)=((L_(x))/(T))^(a) ((L_(y))/(T))^(b)(L_(y))^(c) and we may solve completely as a=1,b=-1 and c=1. The increase in deductive power gained by the use of directed length dimensions is apparent. A conveyer belt of width D is moving along x-axis with velocity V. A man moving with velocity U on the belt in the direction perpedicular to the belt's velocity with respect to belt want to cross the belt. The correct expression for the drift (S) suffered by man is given by (k is numerical costant )