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The number of silicon atoms per m^(3) is...

The number of silicon atoms per `m^(3)` is `5 xx 10^(28)`. This is doped simultaneously with `5 xx 10^(22)` atoms per `m^(3)` of Arsenic and `5 xx 10^(20)` per `m^(3)` atoms of Indium. Calcualte the number of electrons and holes. Given that `n_(i) = 1.5 xx 10^(16) m^(-3)`. Is the material n-type or p-type?

Text Solution

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`n_(c) = 4.95 xx 10^(22), n_(h) = 4.75 xx 10^(9)`, n-type since `n_(e) gt gt n_(h)`
For charge neutrality `N_(D)-N_(A) = n_(e).n_(h) = n_(i)^(2)`
Solving these equations, `n_(e) = 1/2 [(N_(D)-N_(A)) + sqrt((N_(D)-N_(A))^(2) + 4n_(i)^(2))]`
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