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Calculate the orbital period of the elec...

Calculate the orbital period of the electron in the first excited state of hydrogen atom.

Text Solution

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For first excited state h = 2
Bohr's first postulate :
`(mv^(2))/r=(Kze^(2))/r^(2)" ...(i)"`
`"where K "=1/(4piin_(0))`
Bohr's second postulate :
`mvr=(nh)/(2pi)" ...(2)"`
`T=(2pir)/v" ...(3)"`
From equation (1), (2) and (3)
`T=(4in_(0)^(2)h^(3))/(eta_(e)^(4))h^(3)`
`n = 2` ltbtgt `T=(4in_(0)^(2)h^(3))/(etae^(4))xx2^(3)`
`T=((4xx8.85xx10^(-12))xx(6.63xx10^(-34))^(3)xx8)/(9.11xx10^(-31)xx(1.6xx10^(-19))^(4))`
`T=1.22xx10^(-15)sec.`
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Knowledge Check

  • The radius of electron in the first excited state of hydrogen atom is

    A
    `a_0`
    B
    `4a_0`
    C
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    D
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  • The time period of the electron in the ground state of hydrogen atom is two times the times period of the electon in the first excited state of a certain hydrongen like atom (Atomic number Z). The value of Z is

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    C
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    D
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  • The total energy of an electron in the first excited state of hydrogen atom is about -3.4eV . Its kinetic energy in this state is

    A
    `-3.4eV`
    B
    `3.4eV`
    C
    `6.8eV`
    D
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