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A point charge q moving with a velocity ...

A point charge q moving with a velocity `vecv` at a given time in a magnetic field `vecB` experiences a force given as `F = q [vec(v). vecB]`

Text Solution

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The correct Answer is:
False
Lorentz force `vecF = q(vecv xx vecB)`
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Explore conceptually related problems

When we consider a point charge q moving with a velocity vecv at a given time in presence of magnetic field vecB , the charged particle experiences a magnetic force vecF_m = q[vecv xx vecB] . The force was first given by H.A. Lorentz and is called the Lorentz magnetic force. The force depends on q, vecv and vecB and involves a vector product of vecv and vecB . The force acts in a side ways direction perpendicular to both the velocity and magnetic field and the direction is given by right hand thumb rule for vector product. Obviously force on a negative charge is opposite to that on a positive charge. Under what condition does a moving charge experience minimum force due to a magnetic field present there?

When we consider a point charge q moving with a velocity vecv at a given time in presence of magnetic field vecB , the charged particle experiences a magnetic force vecF_m = q[vecv xx vecB] . The force was first given by H.A. Lorentz and is called the Lorentz magnetic force. The force depends on q, vecv and vecB and involves a vector product of vecv and vecB . The force acts in a side ways direction perpendicular to both the velocity and magnetic field and the direction is given by right hand thumb rule for vector product. Obviously force on a negative charge is opposite to that on a positive charge. When will a moving charge experience maximum force due to a magnetic field?

Knowledge Check

  • A charge q is moving with a velocity v_(1)=1hati m/s at a point in a magentic field and experiences a force F=q[-hatj+1hatk] N. If the charge is moving with a voloctiy v_(2)=2hatj m/s at the same point then it experiences a force F_(2)=q(1hati-1hatk) N. The magnetic induction B at that point is

    A
    `(hatl+hatj+hatk)wb//m^(2)`
    B
    `(hatl-hatj+hatk)wb//m^(2)`
    C
    `(-hatl+hatj-hatk)wb//m^(2)`
    D
    `(hatl+hatj-hatk)wb//m^(2)`

    • Similar Questions

    Explore conceptually related problems

    When we consider a point charge q moving with a velocity vecv at a given time in presence of magnetic field vecB , the charged particle experiences a magnetic force vecF_m = q[vecv xx vecB] . The force was first given by H.A. Lorentz and is called the Lorentz magnetic force. The force depends on q, vecv and vecB and involves a vector product of vecv and vecB . The force acts in a side ways direction perpendicular to both the velocity and magnetic field and the direction is given by right hand thumb rule for vector product. Obviously force on a negative charge is opposite to that on a positive charge. Define SI unit of magnetic field on the basis of Lorentz force.

    When we consider a point charge q moving with a velocity vecv at a given time in presence of magnetic field vecB , the charged particle experiences a magnetic force vecF_m = q[vecv xx vecB] . The force was first given by H.A. Lorentz and is called the Lorentz magnetic force. The force depends on q, vecv and vecB and involves a vector product of vecv and vecB . The force acts in a side ways direction perpendicular to both the velocity and magnetic field and the direction is given by right hand thumb rule for vector product. Obviously force on a negative charge is opposite to that on a positive charge. An electron enters a given region moving with an initial velocity vecv = 12.5 hati m s^(-1) where a unifomr magnetic field vecB = B_0 hatj is also applied. What is the direction of force experienced by electron due to the magnetic field?

    When we consider a point charge q moving with a velocity vecv at a given time in presence of magnetic field vecB , the charged particle experiences a magnetic force vecF_m = q[vecv xx vecB] . The force was first given by H.A. Lorentz and is called the Lorentz magnetic force. The force depends on q, vecv and vecB and involves a vector product of vecv and vecB . The force acts in a side ways direction perpendicular to both the velocity and magnetic field and the direction is given by right hand thumb rule for vector product. Obviously force on a negative charge is opposite to that on a positive charge. A charged particle is placed at rest at a point P whose coordinates are (2,3,0) and a magnetic field vecB = 5 xx 10^(-3) hatk is present here. What is the magnetic force experienced by the charge ?

    Moving charges in a magnetic field would experience a force.

    The force vecF experienced by a particle of charge q moving with velocity vecv in a magnetic field vecB is given by vecF = q(vecv xx vecB) . Of these, name the pairs of vectors which are always at right angles to each other.

    An electron moving with velocity vecv_(1)=1hati m//s at a point in a magnetic field experiences a force vecF_(1)=-ehatjN where e is the charge of electron.If the electron is moving with a velocity vecv_(2)=hati-hatj m//s at the same point, it experiences a force vecF_(2)=-e(hati+hatj)N . Find the magnetic field and the force the electron would experience if it were moving with a velocity vecv_(3)=vecv_(1)xxvecv_(2) at the same point.

    Force on a charged particle moving with velocity vecv subjected to a magnetic field is zero. This means:

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