Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage .
As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as :
`E_(n) = - (13.6)/(n^(2)) eV`
The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process.
The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to `n = oo` and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed `(r= oo)` from the nucleus and is at rest.
Now answer the follwoing questions:
What does negative value of atomic energy signify?
Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage .
As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as :
`E_(n) = - (13.6)/(n^(2)) eV`
The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process.
The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to `n = oo` and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed `(r= oo)` from the nucleus and is at rest.
Now answer the follwoing questions:
What does negative value of atomic energy signify?
As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as :
`E_(n) = - (13.6)/(n^(2)) eV`
The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process.
The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to `n = oo` and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed `(r= oo)` from the nucleus and is at rest.

Now answer the follwoing questions:
What does negative value of atomic energy signify?
Text Solution
Verified by Experts
The negative sing of the energy of an electron moving in an orbit in hydrogen atom mean that the electron is bound with the nucleus .
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Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage . As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as : E_(n) = - (13.6)/(n^(2)) eV The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process. The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to n = oo and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed (r= oo) from the nucleus and is at rest. Now answer the follwoing questions: How can a hydrogen atom receive energy to raise the electron to higher energy states ?
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Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage . As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as : E_(n) = - (13.6)/(n^(2)) eV The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process. The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to n = oo and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed (r= oo) from the nucleus and is at rest. Now answer the follwoing questions: Which atomic transition correspond to spectral lines of hydrogen in visible light ?
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Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage . As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as : E_(n) = - (13.6)/(n^(2)) eV The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process. The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to n = oo and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed (r= oo) from the nucleus and is at rest. Now answer the follwoing questions: What is the energy of hydrogen atom and give its value.
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Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage . As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as : E_(n) = - (13.6)/(n^(2)) eV The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process. The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to n = oo and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed (r= oo) from the nucleus and is at rest. Now answer the follwoing questions: Define ionisation energy of hydrogen atom and give its value.
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Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage . As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as : E_(n) = - (13.6)/(n^(2)) eV The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process. The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to n = oo and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed (r= oo) from the nucleus and is at rest. Now answer the follwoing questions: When does a hydrogen atom emit a photon ?
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Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage . As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as : E_(n) = - (13.6)/(n^(2)) eV The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process. The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to n = oo and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed (r= oo) from the nucleus and is at rest. Now answer the follwoing questions: Name the spectral series of hydrogen atom observed in visible light region.
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Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage . As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as : E_(n) = - (13.6)/(n^(2)) eV The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process. The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to n = oo and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed (r= oo) from the nucleus and is at rest. Now answer the follwoing questions: Write the formula for spectral lines the of hydrogen atom in visible light in terms of Rydberg's constant.
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Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage . As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as : E_(n) = - (13.6)/(n^(2)) eV The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process. The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to n = oo and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed (r= oo) from the nucleus and is at rest. Now answer the follwoing questions: Find a relation between wavelengths of first line and series limit of hydrogen spectrum in vissible light.
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Read the pasage given below as well as the adjoining energy level diagram and then answer the questions given after the passage . As per Bohr's theory og hydrogen atom the energy of an atom in a state corresponding to principal quantum number n is given as : E_(n) = - (13.6)/(n^(2)) eV The energy of an atom is the least when its electron is revolving in an orbit closets to the nucleus i.e., the one for which n =1. This state is called the ground state. When a hydrogen atom receives energy by processes such as electron collision , the atom may acquire sufficient energy to raise the electron to higher energy states and the atom is then said to be in an excited state . From these excited states the electron can then fall back to a state of lower energy , emitting a photon in the process. The energy level diagram for the stationary states of a hydrogen atom , compouted from Bohr's relation for energy , is given in Fig.12.02. The principal quantum number n labels the stationary states in the ascending order of energy . Obviously , the highest energy corresponds to n = oo and has an energy of 0 eV. This is the energy of the atom when the electron is completely removed (r= oo) from the nucleus and is at rest. Now answer the follwoing questions: Calculate the wavelenght of first spectral lines of series mentioned in part (g) of question.
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According to Bohr's theory of the hydrogen atom, the radii of stationary electron orbits are related to the principal quantum number n as :
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