Home
Class 12
CHEMISTRY
FeSO(4) solution mixed with (NH(4))(2)SO...

`FeSO_(4)` solution mixed with `(NH_(4))_(2)SO_(4)` solution in 1 : 1 molar ratio gives the test of `Fe^(2+)` ion but `CuSO_(4)` solution mixed with aqueous ammonia in 1 : 4 molar ratio does not give the test of `Cu^(2+)` ion. Explain, why ?

Text Solution

Verified by Experts

`FeSO_(4)` solution mixed with `(NH_(4))_(2)SO_(4)` solution forms a double salt, having the formula `FeSO_(4).(NH_(4))_(2)SO_(4).6H_(2)O` (Mohr salt) which ionises in the solution to give `Fe^(2+)` ions. Hence, it gives the tests of `Fe^(2+)` ions.
`CuSO_(4)` solution mixed with aqueous ammonia forms a complex salt, with the formula `[Cu(NH_(3))_(4)]SO_(4)`. The complex ion, `[Cu(NH_(3))_(4)]^(2+)` does not ionise to give `Cu^(2+)` ions. Hence, it does not give the tests of `Cu^(2+)` ion.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • COORDINATION COMPOUNDS

    U-LIKE SERIES|Exercise CASE BASED/SOURCE-BASED INTEGRATED QUESTION|15 Videos

  • COORDINATION COMPOUNDS

    U-LIKE SERIES|Exercise MULTIPLE CHOICE QUESTIONS|20 Videos

  • COORDINATION COMPOUNDS

    U-LIKE SERIES|Exercise SELF ASSESSMENT TEST|7 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    U-LIKE SERIES|Exercise LONG ANSWER QUESTIONS - I|21 Videos

  • ELECTROCHEMISTRY

    U-LIKE SERIES|Exercise SELF ASSESSMENT TEST (SECTION D)|1 Videos

Similar Questions

Explore conceptually related problems

FeSO_(4) solution mixed with (NH_(4))_(2)SO_(4) solution in 1 : 1 molar ratio gives the test of Fe^(2+) but CuSO_(4) solution mixed with aqueous ammonia in 1 : 4 molar ratio does not give the test of Cu^(2+) ion. Explain why ?

FeSO_4 solution mixed with (NH_4)_2SO_4 solution is 1:1 molar ratio gives the test of Fe^(2+) ion but CuSO_4 solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu^(2+) ion. Explain why?

Knowledge Check

  • KI and CuSO_4 solution when mixed give .

    A
    `Cu l_2 + K_2SO_4`
    B
    `Cu_2I_2 + K_2SO_4`
    C
    `K_2SO_4 + CU_2I_2 +I_2`
    D
    `K_2SO_4 + CuI_2I_2`

  • KI and CuSO_4 solutions when mixed give

    A
    `CuI_2+K_2SO_4`
    B
    `Cu_2I_2+K_2SO_4`
    C
    `K_2SO_4+Cu_2I_2+I_2`
    D
    `K_2SO_4+CuI_2+I_2`

  • Which of the following salt does not give test of Fe^(+2) ion in aq solution :-

    A
    `FeSO_4(NH_4)_2SO_(4)6H_2O`
    B
    `Fe_3[Fe(CN)_6]_2`
    C
    `Fe_4[Fe(CN)_6]_3`
    D
    (2) and (3)

    • Similar Questions

    Explore conceptually related problems

    K_(2)SO_(4) solution mixed with Cr_(2)(SO_(4))_(3) solution in 1:1 molar ratio gives the test of Cr^(3+) ion but CuSO_(4) solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu^(2+) ion. Explain why ?

    FeSO_(4) solution mixed with (NH_(4))_(2)SO_(4) solution (in molar ratio 1 : 1) gives the test of Fe^(2+) ion but CuSO_(4) solution mixed with liquid NH_(3) (in the molar ratio 1 : 4 ) does not give the test of Cu^(2+) . Explain why.

    Cu^(2+) ions with NH_(4)OH solution gives

    The solution of the compound, K_(4)Fe(CN)_(6) will not given the tests of …… and …… ions.

    Consider the following experiments and answer the questions at the end of it (A) When Fe(CN)_(2) solution is treated with KCN solution species formed no longer gives tests of Fe^(2+) and CN^(Θ) (B) When K_(2)SO_(4) solution is treated with A1_(2)(SO_(4))_(3) solution species formed gives tests of K^(o+),A1^(3+) and SO_(4)^(2-) Species formed in experiment A does not give test of Fe^(2+) and CN^(Θ) it is due to formation of .

    Home
    Profile