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find the equation of hyperabola where fo...

find the equation of hyperabola where foci are (0,12) and (0,-12)and the length of the latus rectum is 36

Text Solution

Verified by Experts

Here, Foci of hyperbola `= (0,+-12)`
That means the transverse axis of the hyperbola is `Y`-axis.
So, the equation will be of the type,
`y^2/a^2-x^2/b^2 = 1->(1)`
Also, `c = 12`
Length of latus rectum ` = 36`
`:. 2b^2/a = 36=> b^2 = 18a`
In a hyperbola, `c^2 = a^2+b^2`
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Knowledge Check

  • The equation of the hyperbola whose foci are (pm 4, 0) and length of latus rectum is 12 is

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