Find the intervals in which the function f given by `f(x)=2x^2-3x`is(a) strictly increasing (b) strictly decreasing

Explanation

To find the intervals in which the function \( f(x) = 2x^2 - 3x \) is strictly increasing and strictly decreasing, we will follow these steps:

### Step 1: Find the derivative of the function
To determine where the function is increasing or decreasing, we first need to find the derivative of the function \( f(x) \).

\[ f'(x) = \frac{d}{dx}(2x^2 - 3x) = 4x - 3 \]
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