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A geyser heats water flowing at the rate...

A geyser heats water flowing at the rate of 3 kg per minute from `27^(@)C` to `77^(@)C` . If the geyser operates on a gas burner, what is the rate of consumption of fuel if the heat of combustion is `4 xx 10^(4) J//g?` Given specific heat of water is `4.2 xx 10^(3) J//kg//K`.

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To solve the problem step by step, we will calculate the rate of consumption of fuel required to heat water in a geyser. ### Step 1: Identify the given data - Mass flow rate of water, \( m = 3 \, \text{kg/min} \) - Initial temperature, \( T_1 = 27^\circ C \) - Final temperature, \( T_2 = 77^\circ C \) - Specific heat of water, \( C = 4.2 \times 10^3 \, \text{J/kg/K} \) - Heat of combustion of fuel, \( H_c = 4 \times 10^4 \, \text{J/g} \) ...
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Find the result of mixing 0.5 kg ice at 0^@C with 2 kg water at 30^@C . Given that latent heat of ice is L=3.36xx10^5 J//kg and specific heat of water is 4200 J//kg//K .

500 kg of water is heated from 20^(@) to 100^(@) C . Calculate the increase in the mass of water.Given specific heat of water =4.2 xx 10^(3) J kg ^(-1) .^(@)C^(-1) .

Knowledge Check

  • A geyser heats water flowing at the rate of 4 litre per minute from 30^(@) "to" 85^(0) C . If the geyser operates on a gas burner then the amount of heat used per minute is

    A
    `9.24xx10^(5)J`
    B
    `6.24xx10^(7)J`
    C
    `9.24xx10^(7)J`
    D
    `6.24xx10^(5)J`
  • An ice cube of mass 0.1 kg at 0^@C is placed in an isolated container which is at 227^@C . The specific heat s of the container varies with temperature T according to the empirical relation s=A+BT , where A= 100 cal//kg.K and B = 2xx 10^-2 cal//kg.K^2 . If the final temperature of the container is 27^@C , determine the mass of the container. (Latent heat of fusion for water = 8xx 10^4 cal//kg , specific heat of water =10^3 cal//kg.K ).

    A
    0.495 kg
    B
    0.595 kg
    C
    0.695 kg
    D
    0.795 kg
  • An ice cube of mass 0.1 kg at 0^@C is placed in an isolated container which is at 227^@C . The specific heat s of the container varies with temperature T according to the empirical relation s=A+BT , where A= 100 cal//kg.K and B = 2xx 10^-2 cal//kg.K^2 . If the final temperature of the container is 27^@C , determine the mass of the container. (Latent heat of fusion for water = 8xx 10^4 cal//kg , specific heat of water =10^3 cal//kg.K ).

    A
    `0.495 kg`
    B
    `0.595 kg`
    C
    `0.695 kg`
    D
    `0.795 kg`
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    How should 1 kg of water at 50^(@)C be divided in two parts such that if one part is turned into ice at 0^(@)C . It would release sufficient amount of heat to vapourize the other part. Given that latent heat of fusion of ice is 3.36xx10^(5) J//Kg . Latent heat of vapurization of water is 22.5xx10^(5) J//kg and specific heat of water is 4200 J//kg K .

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    An ice cube of mass 0.1 kg at 0^@C is placed in an isolated container which is at 227^@C . The specific heat s of the container varies with temperature T according to the empirical relation s=A+BT , where A= 100 cal//kgK and B = 2xx (10^-2) cal//kg . If the final temperature of the container is 27^@C , determine the mass of the container. (Latent heat of fusion for water = 8xx (10^4) cal//kg , specific heat of water =10^3 cal//kg-K ).