The conductivity of `0.20M` solution of `KCl` at `298K` is `0.0248 S cm^(-1)` . Calculate its molar conductivity.

Explanation

To calculate the molar conductivity of a 0.20 M solution of KCl at 298 K, we can use the following formula:

\[ \Lambda_m = \frac{\kappa \times 1000}{C} \]

Where:
- \(\Lambda_m\) = molar conductivity (in S cm\(^2\) mol\(^{-1}\))
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