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The ratio of the wavelengths of a photon...

The ratio of the wavelengths of a photon and that of an electron of same energy E will be [m is mass of electron ]

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The ratio of de-Broglie wave length of a photon and an electron of mass 'm' having the same kinetic energy E is: (Speed of light=c)

Find the ratio of the respective kinetic energies of a photon to that of an electron if it is known that the de Broglie wavelength of the electron moving with a velocity of 2 xx 10^(8 )m s^(-1) is equal to that of the photon.

Knowledge Check

  • Calculate the wavelength of a photon having an energy of 2 electron volt

    A
    `6.204 xx 10^(-7)m`
    B
    `6.206 xx 10^(-6)m`
    C
    `6.204 xx 10^(-9)m`
    D
    `6.204xx10^(-8)m`

  • Calculate the wavelength of a photon having an energy of 2 electron volt

    A
    `6.204 xx 10^(-7)m`
    B
    `6.206 xx 10^(-6)m`
    C
    `6.204 xx 10^(-9)m`
    D
    `6.204xx10^(-8)m`

  • If m is the mass of an electron and c the speed of light, the ratio of the wavelength of a photon of energy E to that of the electron of the same energy is

    A
    `csqrt((2m)/(E))`
    B
    `sqrt((2m)/(E))`
    C
    `sqrt((2m)/(cE))`
    D
    `sqrt((m)/(E))`

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    The de-Broglie wavelength of an electron is the same as that of a 50 ke X-ray photon. The ratio of the energy of the photon to the kinetic energy of the electron is ( the energy equivalent of electron mass of 0.5 MeV)

    The wavelength lambda_(e ) of an photon of same energy E are related by

    If m is the mass of an electron and c is the speed of light then the ratio of wavelength of a photon of energy E to that of the electron of the same energy is

    Assertion : If the wavelength lamda of photon and de Broglie wavelength of electron are same , their energy is also same. Reason : Momentum of both the particles is same by de Broglie hypothesis.

    The wavelength lamda_(e) of ann electron and lamda_(p) of a photon of same energy E are related by

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