Home
Class 12
CHEMISTRY
Silver forms ccp lattice and x-ray studi...

Silver forms ccp lattice and x-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate the density of silver. (Atomic mass of Ag = 107.9 u)

Text Solution

Verified by Experts

Since the lattice is ccp, the number of silver atoms per unit cell (Z) = 4
Molar mass of silver = 107.9 g `mol^(-1) = 107.9 xx 10^(-3) kg" "mol^(-1)`
Edge length of unit cell (a) = 408.6 pm = 408.6 `xx 10^(-12)` m
Density, d `= (Z.M)/(a^(3).N_(A))`
`= (4 xx (107.9 xx 10^(-3)kg" "mol^(-1)))/((408.6 xx 10^(-12) m)^(3) (6.022 xx 10^(23) mol^(-1)))`
`= 10.5 xx 10^(3) kg" "m^(-3)`
10.5 gm `cm^(-3)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLID STATE

    OSWAAL PUBLICATION|Exercise TOPIC -1 (LONG ANSWER TYPE QUESTIONS - I)|12 Videos

  • SOLID STATE

    OSWAAL PUBLICATION|Exercise TOPIC -1 (LONG ANSWER TYPE QUESTIONS - II)|3 Videos

  • SOLID STATE

    OSWAAL PUBLICATION|Exercise TOPIC -1 (VERY SHORT ANSWER TYPE QUESTIONS )|14 Videos

  • Sample Paper 8

    OSWAAL PUBLICATION|Exercise EXCERSICE|54 Videos

  • SOLUTIONS

    OSWAAL PUBLICATION|Exercise TOPIC - 3 COLLIGATIVE PROPERTIES , DETERMINATION OF MOLAR MASS, ABNORMAL MOLAR MASS, VAN.T HOFF FACTOR (LONG ANSWER TYPE QUESTIONS - II)|18 Videos

Similar Questions

Explore conceptually related problems

Silver forms CCP lattice and x-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate the density of silver (Atomic mass of Ag = 107. 9u).

Silver froms ccp lattice and X -ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate the density of silver (atomic mass = 107.9 u ).

Silver crystallizes in CCP lattice. The edge length of its unit cell is 408.6 pm. Calculate density of silver (atomic mass of silver is 107.9)

Silver forms a ccp lattice. The edge length of its unit cell is 408.6 pm. Calculate the density silver (N_A=6.022xx10^(23) , Atomic mass of Ag=108 gmol^(-1) )

Silver forms a ccp lattice. The edge length of its unit cell is 408.6 pm. Calculate the density of silver. ( N_(A)=6.022xx10^(23) , Atomic mass of Ag=108 gmol^(-1) ).

a. Calculate the packing efficiency in a Body Centered Cubic (BCC) lattice. b. Silver forms a ccp lattice. The edge length of its unit cell is 408.6 pm. Calculate the density of silver. (N_(A)=6.022xx10^(23)," Atomic mass of Ag "=108 g mol^(-1))

An element having atomic mass 107.9 g mol^(-1) has FCC unit cell. The edge length of the unit cell is 486 pm. Calculate the density of the unit cell.

Silver metal crystallises with a face centred cubic lattice. The length of unit cell is formed to be 4.077 xx 10^(-8) cm. Calculate atomic radius and density of silver. (Atomic mass of Ag = 108 u, N_(A) = 6.023 xx 10^(23) mol^(-1) ).

An element crystallizes in fcc lattice. If the edge length of the unit cell is 408.6 pm and the density is 10.5 g cm^(-3) . Calculate the atomic mass of the element.

Answer any five of the following questions. Lithium metal has a body centred cubic lattice structure with edge length of edge unit cell 352 pm. Calculate the density of lithium metal. [Given: Atomic mass of Li = 7 "gmol"^(-1) , N_(A) = 6.022 xx 10^(23) atoms mol ""^(-1) ].

Home
Profile