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A constant force F = m(2)g//2 is applie...

A constant force `F = m_(2)g//2` is applied on the block of mass nij as shown. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of `m_(1)`

A

`(m_(2)g)/(2m_(1))`

B

`(m_(2)g)/(2(m_(1) +m_(2))`

C

`(3m_(2)g)/(2(m_(1) + m_(2))`

D

`(3m_(2)g)/((2m_(1))`

Text Solution

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The correct Answer is:
B
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