Home
Class 12
CHEMISTRY
A stream of dry air was passed through a...

A stream of dry air was passed through a bulb containing a solution of 7.5 g of a compound dissolved in 75 g of water and then through another bulb containing pure water. The loss of mass in the first bulb was 2.81 g and in the second bulb was 0.054 g. Calculate the molecular mass of the compound.

Text Solution

Verified by Experts

` M_(2) = (P^(0)(W_(2)M_(1)))/((P^(0) - P)W_(1))`
OR
`M_(2) = (W_(2) M_(1))/(W_(1)) xx ((P^(0))/(P^(0)-P))`
`("Total loss in mass of solution bulb and the solvent bulb")/("Loss in mass of solvent bulb")`
= `(7.5 xx 18)/(75) xx (2.864)/(0.054)`
`M_(2) = 95.47`.
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    OSWAAL PUBLICATION|Exercise TOPIC - 3 COLLIGATIVE PROPERTIES , DETERMINATION OF MOLAR MASS, ABNORMAL MOLAR MASS, VAN.T HOFF FACTOR (VERY SHORT ANSWER TYPE QUESTIONS )|16 Videos

  • SOLUTIONS

    OSWAAL PUBLICATION|Exercise TOPIC - 3 COLLIGATIVE PROPERTIES , DETERMINATION OF MOLAR MASS, ABNORMAL MOLAR MASS, VAN.T HOFF FACTOR (SHORT ANSWER TYPE QUESTIONS)|11 Videos

  • SOLUTIONS

    OSWAAL PUBLICATION|Exercise TOPIC - 2 VAPOUR PRESSURE, RAOULT.S LAW , IDEAL AND NON-IDEAL SOLUTIONS ( SHORT ANSWER TYPE QUESTIONS )|12 Videos

  • SOLID STATE

    OSWAAL PUBLICATION|Exercise TOPIC -2 (SHORT ANSWER TYPE QUESTIONS)|21 Videos

  • Solved Paper

    OSWAAL PUBLICATION|Exercise Exercise|60 Videos

Similar Questions

Explore conceptually related problems

Dry air was passed successively through a solution of 5 gm of solute dissolved in 80.0 gm of water and through pure water. The loss in weight of the solution was 2.5 gm and that of the pure solvent was 0.04 gm. What is the molecular weight of the solute?

4.375 g of a substance when dissolved in 36.0 g of water, lowered its vapour pressure by 0.5 mm at a given temperature. The vapour pressure of water at this temperature is 25.0 mm . Calculate the molecular weight of solute.

The vapour pressure of a solution cont.aning 10 g of a non-electrolyte in 200 g of water at a particular temperature is 2985 Pa. The vapour pressure of pure water at that temperature is 3000 Pa. Calculate the molecular mass of the solute.

Calculate the molality of an aqueous solution containing 3.0g of urea (mol.mass=60) in 250g of water.