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A lift is going up with constant velocit...

A lift is going up with constant velocity `v_(0)`. Calculate the work done by normal force `F_(g)` from the reference frame of ground and lift in time t.

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The correct Answer is:
`F_(N)`.ut; zero
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Knowledge Check

  • A block of 1 kg is kept on a rough surface of an elevator moving up with constant velocity of 5 m/s. In 10 second work done by normal reaction (no sliding on incline surface) (i) from ground frame is 320 J (ii) is equal to work done by friction force in elevator frame (iii) is equal to work done by friction in ground frame

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