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Define ionic product of water. The degre...

Define ionic product of water. The degree of dissociation of pure water at `18^(@)C` is found to be `1.8times10^(-9)` Find the final ionic product of water and its dissociation constant at `18^(@)C`

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The degree of dissociation of pure water at 18^@C is found to be 1.8 xx 10^(-9) . Find ionic product of water and its dissociation constant at 18^@C .

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Knowledge Check

  • The degree of dissociation of 100 mL of pure water at 25^(@)C is

    A
    `1.8xx10^(-16)`
    B
    `1xx10^(-14)`
    C
    `1.8xx10^(-9)`
    D
    `1.0`

  • Ionic product of water increases, if

    A
    Pressure is reduced
    B
    Temperature increases
    C
    `OH^(-)` is added
    D
    Temperature increases

  • Ionic product of water increases, if

    A
    `H^+` ions are added
    B
    OH ions are added
    C
    Temperature decreases
    D
    Temperature increases

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