Home
Class 12
CHEMISTRY
Statement 1: The standard emf (E(cell)^(...

Statement 1: The standard emf `(E_(cell)^(@))` of following concentration cell is zero.
`Zn(s)|ZnSO_(4)(C_(1))||ZnSO_(4)(C_(2))|Zn(s)`
Statement 2: The electrolyte concentration cell will be is greater in cathodic half-cell.

A

Statement 1 is true, statement 2 is true, statement 2 is a correct explanation for statement 1

B

Statement 1 is true, statement 2 is true, statement 2 is not a correct explanation for statement 1

C

Statement 1 is true, statement 2 is false

D

statement 1 is false,statement 2 is true

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will break down the concepts involved in the concentration cell and the electrochemical principles that govern it. ### Step-by-Step Solution: 1. **Understanding the Concentration Cell**: - The given concentration cell is represented as: \[ \text{Zn(s)} | \text{ZnSO}_4(C_1) || \text{ZnSO}_4(C_2) | \text{Zn(s)} \] - In this cell, both half-cells contain the same metal (Zn) and the same type of electrolyte (ZnSO4) but at different concentrations (C1 and C2). 2. **Standard EMF of the Cell**: - The standard EMF (E°) of a concentration cell is calculated using the formula: \[ E°_{\text{cell}} = E°_{\text{cathode}} - E°_{\text{anode}} \] - Since both half-cells involve the same metal, the standard electrode potentials (E°) for both the cathode and anode are equal, leading to: \[ E°_{\text{cell}} = 0 \] - Therefore, **Statement 1** is correct: The standard EMF of the concentration cell is zero. 3. **Understanding the Cathodic and Anodic Reactions**: - In a concentration cell, the half-cell with the higher concentration (C2) acts as the cathode, while the half-cell with the lower concentration (C1) acts as the anode. - The cell reaction can be described as: \[ \text{Zn}^{2+}(C_2) + 2e^- \rightarrow \text{Zn(s)} \quad (\text{cathode}) \] \[ \text{Zn(s)} \rightarrow \text{Zn}^{2+}(C_1) + 2e^- \quad (\text{anode}) \] 4. **Evaluating Statement 2**: - Statement 2 claims that the electrolyte concentration in the cathodic half-cell will be greater than that in the anodic half-cell. - This is true, as the cathodic half-cell (C2) has a higher concentration than the anodic half-cell (C1). - Thus, **Statement 2** is also correct. 5. **Conclusion**: - Both statements are true, but Statement 2 does not explain why the standard EMF is zero. It merely states a fact about the concentrations in the half-cells without linking it to the EMF being zero. ### Final Answer: - **Statement 1** is true: The standard EMF \( E°_{\text{cell}} \) of the concentration cell is zero. - **Statement 2** is true: The electrolyte concentration in the cathodic half-cell is greater than that in the anodic half-cell. - However, Statement 2 does not provide a valid explanation for Statement 1.

To analyze the statements provided in the question, we will break down the concepts involved in the concentration cell and the electrochemical principles that govern it. ### Step-by-Step Solution: 1. **Understanding the Concentration Cell**: - The given concentration cell is represented as: \[ \text{Zn(s)} | \text{ZnSO}_4(C_1) || \text{ZnSO}_4(C_2) | \text{Zn(s)} ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ERRORLESS |Exercise Jee Section (Comprehension Type question)|13 Videos
  • ELECTROCHEMISTRY

    ERRORLESS |Exercise Jee Section (Integer type Questions)|5 Videos
  • ELECTROCHEMISTRY

    ERRORLESS |Exercise Jee Section (More than one choice correct answer)|10 Videos
  • D & P-BLOCK ELEMENTS

    ERRORLESS |Exercise JEE Section (Numeric answer type questions)|2 Videos
  • ENVIRONMENTAL CHEMISTRY

    ERRORLESS |Exercise CRITICAL THINKING (Objective question )|16 Videos

Similar Questions

Explore conceptually related problems

Calculate the EMF of the following concentration cell at 298K Zn|ZnSO_(4)(0.05M)||ZnSO_(4)(0.5M)|Zn

EMF of the cell Zn ZnSO_(4)(a =0.2)||ZnSO_(4)(a_(2))|Zn is -0.0088V at 25^(@)C . Calculate the value of a_(2) .

Knowledge Check

  • Consider the following concentration cell : Zn(s)|Zn^(2+)(0.024M)||Zn^(2+)(0.480M)|Zn(s) which of the following statements is // are correct?

    A
    The `EMF` of the cell at `25^(@)C` is nearly `+0.039V.`
    B
    The `EMF` of the cell at `25^(@)C` is nearly `-0.039V`.
    C
    If water is added in `LHE`, so that the `[Zn^(2+)]` is reduced to `0.012 M`, the cell voltage increases.
    D
    If water is added in `LH` , so that the `[Zn^(2+)]` is reduced to `0.012M` , the cell voltage decreases.
  • In a concentration cell, Zn|Zn^(2+) (0.1M) || Zn^(2+) (0.15M) | Zn , as the cell discharges:

    A
    reaction proceeds to the right
    B
    the two solutions approach each other in concentration.
    C
    no reaction takes place
    D
    water gets decomposed.
  • Calculate EMF of following cell at 298 K Zn|ZnSO_(4) (0.1 M) ||CuSO_(4) (1.0 M)|Cu (s) if E_(cell) = 2.0 V

    A
    `2.0296 V `
    B
    `2.0592 V`
    C
    `1.0508 V `
    D
    `2.0` V
  • Similar Questions

    Explore conceptually related problems

    For the following cell Zn(s)|ZnSO_4 (aq) ||CuSO_4 (aq)|Cu(s) When [Zn^(2+)] is ten times of [Cu^(2+)] the expression Delta G ( in J mol^-1 ) is

    The emf of the Daniel cell using molar concentrations of ZnSO_(4) and CuSO_(4) solutions is

    The e.m.f of the following cell, Zn |ZnSO_(4) (1M)||H^(+)(1M)|H_(2(g))1atm|Pt is 0.769 Volts. The reduction potential of Zn electrode will be_________.

    Zn | Zn^(2+)(C_(1) || Zn^(2+)(C_(2)| Zn . For this cell DeltaG is negative if:

    You are given the following cell at 298 K with E_(cell)^(@)=1.10V Zn(s)|Zn^(2+)(C_(1))||Cu^(++)(C_(2))|Cu(s) where C_(1) and C_(2) are the concentration in mol/lit then which of the following figures correctly correlates E_(cell) as a function of concentrations x-axis log((C_(1))/(C_(2))) and y-axis E_(cell)