Match the nature of aqueous solutions of the substances listed in Column I with the character listed in Column II.
`{:(,"Column I",,"Column II"),((A),KCN_((aq)),(p),"Strongly basic"),((B),TiOH_((aq)),(q),"Neutral"),((C),BeCl_(2(aq)),(r),"Weakly basic"),((D),NaNO_(3(aq)),(s),"Weakly acidic"):}`

Explanation

To solve the problem of matching the nature of aqueous solutions of the substances listed in Column I with the characteristics listed in Column II, we will analyze each substance in Column I and determine its behavior in an aqueous solution.

### Step-by-Step Solution:

1. **Analyzing KCN (Column I, A)**:
- KCN is a salt formed from a strong base (KOH) and a weak acid (HCN).
- When KCN dissolves in water, it dissociates into K⁺ and CN⁻ ions. The CN⁻ ion can hydrolyze to produce OH⁻ ions, making the solution basic.
- **Conclusion**: KCN is **strongly basic**.
- **Match**: A → p (Strongly basic)

2. **Analyzing TiOH (Column I, B)**:
- TiOH (Titanium hydroxide) is a base.
- It does not completely dissociate in water and is considered a weak base.
- **Conclusion**: TiOH is **weakly basic**.
- **Match**: B → r (Weakly basic)

3. **Analyzing BeCl₂ (Column I, C)**:
- BeCl₂ is a salt formed from a weak base (Be(OH)₂) and a strong acid (HCl).
- In aqueous solution, BeCl₂ can hydrolyze to produce H⁺ ions, leading to a slightly acidic solution.
- **Conclusion**: BeCl₂ is **weakly acidic**.
- **Match**: C → s (Weakly acidic)

4. **Analyzing NaNO₃ (Column I, D)**:
- NaNO₃ is a salt formed from a strong base (NaOH) and a strong acid (HNO₃).
- It does not hydrolyze in water and results in a neutral solution with a pH of 7.
- **Conclusion**: NaNO₃ is **neutral**.
- **Match**: D → q (Neutral)

### Final Matches:
- A → p (Strongly basic)
- B → r (Weakly basic)
- C → s (Weakly acidic)
- D → q (Neutral)

### Summary of Matches:
- A (KCN) → p (Strongly basic)
- B (TiOH) → r (Weakly basic)
- C (BeCl₂) → s (Weakly acidic)
- D (NaNO₃) → q (Neutral)