An electron falls through a distance of 1.5cm in a uniform electric field of magnitude `2 times 10^4 NC^-1`. The direction of the field is reversed keeping its magnitude unchanged and a proton falls through the same distance. Compute the time of fall in each case.

An electron falls throgh a distance of 1.5 cm in a uniform electric field of magnitude 2.0 xx10^(4) N c^(-1) the direction of the field is reversed keeping its magnitude unchanged and a proton falls through the same distance compute the time of falls in each case contrast the situation with that of free fall under gravity

An electron falls through a distance of 2 cm ir a uniform electric field of magnitude 6.0 xx 10^4 NC^(-1) figure (a). The direction of the field is reversed keeping its magnitude unchanged and a proton falls through the same distance figure (b). Compute the time of fall ir each case. Contrast the situation with that oi 'free fall under gravity'. m_(e) = 9.1 xx 10^(-31)kg, m_(p) = 1.7 xx 10^(-27) kg and e = 1.6 xx 10^(-19) C

An electron falls from rest through a vertical distance h in a uniform and vertically upward directed electric field E. The direction of electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance h. The time of fall of the electron, in comparison to the time of fall of the proton is

An electron falls freely in electric field of 9.1 xx 10^3 NC^(-1) , then acceleration of electron is .......

An electron of mass m_(e ) initially at rest moves through a certain distance in a uniform electric field in time t_(1) . A proton of mass m_(p) also initially at rest takes time t_(2) to move through an equal distance in this uniform electric field.Neglecting the effect of gravity, the ratio of t_(2)//t_(1) is nearly equal to

A molecule of a substance has a permanent electric dipole moment of magnitude 10^(-30) Cm. A mole of this substance is polarised (at low temperature) by applying a strong electrostatic field of magnitude 10^(7) vm^(-1) . The direction of the field is suddenly changed by an angle of 60^(@) . Estimate the heat released by the substance in aligning its dipole along the new direction of the field. For simplicity assume 100 % polarisation of the sample. 1 mole = 6 xx 10^(23) molecule.

An electric dipole is at 30° with uniform electric field of 2 xx 10^(5) N/C. The torque acting on it is 4 Nm. If length of dipole is 2 cm, then what will be the charge at one end of dipole ?

A molecule of a substance has a permanent electric dipole moment of magnitude 10^(-29) C m. A mole of this substance is polarised (at low temperature) by applying a strong electrostatic field of magnitude 10^(6) V m^(-1) . The direction of the field is suddenly changed by an angle of 60^(@) . Estimate the heat released by the substance in aligning its dipoles along the new direction of the field. For simplicity, assume 100% polarisation of the sample.

An electric dipole with dipole moment 4 xx 10^(-9) Cm is aligned at 30° with the direction of a uniform electric field of magnitude 5 xx 10^4 NC^(-1) . Calculate the magnitude of the torque acting on the dipole.