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A gaseous system absorbs 450 cal heat. T...

A gaseous system absorbs 450 cal heat. The work done by the system is 836.2 J. Find the change in internal energy of the gas in calorie. (J=4.186 J `"cal"^(-1)`)

Text Solution

Verified by Experts

`DeltaQ`=450 cal (here heat is absorbed by the system and hence positive)
`DeltaW`= 837.2 J =`"837.2 J"/("4.186 J cal"^(-1))`=200 cal
(Here work is positive because it is done by the system )
Now, from the first law of thermodynamics,
`DeltaQ=DeltaU+DeltaW`
`therefore DeltaU=DeltaQ-DeltaW`
=450-200
`therefore DeltaU`=250 cal
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