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The area A of a parallel plate capacitor...

The area A of a parallel plate capacitor is divided into two equal, halves and filled with two media of dielectric constants `K_1 and K_2` respectively. The capacitance of the capacitor will be

A

`(epsi_0 A (K_1 + K_2))/d`

B

`(epsi_0A)/d ((K_1 + K_2)/2)`

C

`(epsi_0A)/d. (K_1K_2)/((K_1 + K_2))`

D

`(epsi_0A)/(2d). (K_1 K_2)/((K_1 +K_2))`

Text Solution

Verified by Experts

The correct Answer is:
B
The given arrangement is a combination of two capacitors in parallel whose capacitances are
`C_1 = (K_1 epsi_0 (A/2))/d andC_2 = (K_2 epsi_0(A/2))/drArrC = C_1 + C_2 = (epsi_0A)/d ((K_1 +K_2)/2)`
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Knowledge Check

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