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Figure shows the variation of intensity ...

Figure shows the variation of intensity of magnetisation `vecM` versus the applied magnetic field intensity `vecH` for two materials A and B:
(a) Identify the materials A and B.
(b) Why does the material B, have a larger susceptibility than A for a given field at constant temperature ?

Text Solution

Verified by Experts

(a) Material A is diamagnetic because its magnetisation is negative
Material B is paramagnetic having positive magnetisation .
(b) Magnetic susceptibility ` x = M/H` and its value is given by slope of M - H curve. As slope of curve for material B is greater, hence B has a large susceptibility than A for a given field at constant temperature.
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Knowledge Check

  • The stress versus strain graphs for wires of two materials A and B are as shown in the figure. If Y_(A) and Y_(B) are the younng's moduli of the materials, then

    A
    `Y_(B) = 2Y_(A)`
    B
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    C
    `Y_(B)=3Y_(A)`
    D
    `Y_(A)=3Y_(B)`
  • The stress versus strain graphs for wires of two materials A and B are as shown in the figure. If YA and YB are the Young's moduli of the materials then

    A
    `Y_B=2Y_A`
    B
    `Y_A=Y_B`
    C
    `Y_B=3Y_A`
    D
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  • The magnetic induction and magnetising field intensity in a sample of magnetic material are B and H respectively . The magnetic susceptibility of the material is

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    C
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