A block of mass m is pulled along a horizontal suface by applying a force at an angle q with the horizontal. If the block travels with a uniform velocity and has a displacement d and the coefficient of friction is `mu`, then the work done by the applied force is 

Options

A. `(mu m gd)/(cos theta + mu sin theta)`
B. `(mu m gd cos theta)/(cos theta+ mu sin theta)`
C. `(mu m gd sin theta)/(cos theta + mu sin theta)`
D. `(mu g d cos theta)/(cos theta - mu sin theta)`

Answer

B