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A block of mass m is pulled along a hori...

A block of mass m is pulled along a horizontal suface by applying a force at an angle q with the horizontal. If the block travels with a uniform velocity and has a displacement d and the coefficient of friction is `mu`, then the work done by the applied force is 

A

`(mu m gd)/(cos theta + mu sin theta)`

B

`(mu m gd cos theta)/(cos theta+ mu sin theta)`

C

`(mu m gd sin theta)/(cos theta + mu sin theta)`

D

`(mu g d cos theta)/(cos theta - mu sin theta)`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • A block of mass m is pulled along a horizontal surface by applying a force at an angle theta , with the horizontal. If the block k travels with a uniform velocity and has a displacement d and the coefficient of friction is mu . Then find the workdone by the applied force?

    A
    `(mu mgd)/((cos theta+mu sin theta))`
    B
    `(mu m gd cos theta)/((cos theta+mu sin theta))`
    C
    `(mu mg d sin theta)/((cos theta+mu sin theta))`
    D
    `(mu mg d cos theta)/((cos theta+mu sin theta))`

  • A horizontal force F is applied to applied to a homogeneous rectangular block of massm, width b and height H. The block moves with constant velocity and the coefficient of friction is mu_(k)

    A
    `(b)/(2mu_(s))`
    B
    `(b)/(mu_(s))`
    C
    `(b)/(sqrt(2)mu_(s))`
    D
    `2bmu_(s)`

  • A wooden block of mass M resting on a rough horizontal surface is pulled with a force T at an angle q to the horizontal. If m is coefficient of kinetic friction between the block and the surface, the acceleration of the block is

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    C
    `T/m (cos theta - mu sin theta) - mu g`
    D
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