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An arbitrary surface encloses a dipole. ...

An arbitrary surface encloses a dipole. What is the electric flux through this surface ?

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According to Gauss.s law, the flux associated with close surface is `phi =(sumq)/epsilon_(0)` where q is charge enclosed by closed surface.
Net charge on dipole `=-q + q=0`
`therefore` Flux associated with closed surface enclosing dipole, `phi = (-q+q)/epsilon_(0)=0`
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