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Magnetic susceptibility of a material of...

Magnetic susceptibility of a material of a rod is 499. Find absolute permeability of the material of the rod.

A

`pi xx 10^(-4) ( Tm )/( A)`

B

`4pi xx 10^(-4) (Tm )/( A)`

C

`3pi xx 10^(-4) (Tm )/( A)`

D

`2pi xx 10^(-4) (Tm )/( A)`

Text Solution

Verified by Experts

The correct Answer is:
D
`mu_(r) = chi_(m) +1`
`therefore (mu)/( mu_0) = chi_(m) +1 " "(because mu_(r) = (mu)/( mu_0) )`
`therefore mu= mu_(0) (chi_(m) +1) = 4pi xx 10^(-7) (499 +1)`
`therefore mu= 2pi xx 10^(-4) ( Tm )/( A)`
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Knowledge Check

  • A magnetic needle kept on horizontal surface oscillates in Earth's magnetic field. If the temperature of this needle is raised beyond the Curie temperature of the material of the needle, then ........ .

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  • mu_0 is permeability of vacuum, chi_m is susceptibility then permeability of material is

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    `mu=mu_0(chi_m-1)`
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  • mu_0 is permeability of vacuum, chi_(m) is susceptibility, then permeability of a material…

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