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The line x/a+y/b=1 cuts the coordinate a...

The line `x/a+y/b=1` cuts the coordinate axes at a and B a line perpendicular to AB meets the axes in P and Q. The equation of the locus of the point of intersection of the lines AQ and BP is

A

`x^(2)+y^(2)=a^(2)+b^(2)`

B

`x^(2)+y^(2)=a^(2)`

C

`x^(2)+y^(2)-ax-by=0`

D

`x^(2)+y^(2)+ax+by=0`

Text Solution

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The correct Answer is:
C
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