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Find the equation of tangent to y^(2) = ...

Find the equation of tangent to `y^(2) = 16x` inclined at an angle `60^(@)` with its axis also find its point of contact.

Text Solution

Verified by Experts

The correct Answer is:
`3x-sqrt(3y) +4=0, ((4)/(3), (8)/(sqrt(3)))`
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Find the equation of tangent to the parabola y(2)=16x inclined at an angle 60^(@) with its axis and also find the point of contact.

Find the equation of tangent to the parabola y^(2) = 16x inclined at an angle 60°with its axis and also find the point of contact.

Knowledge Check

  • The equation of the tangent to the circle x^(2)+y^(2)=16 which are inclined at an angle of 60^(@) to the x-axis is

    A
    `y=sqrt3x pm8`
    B
    `x=sqrt3x pm 8`
    C
    `2y=sqrt3x-8`
    D
    `2x=sqrt3x-8`

  • The tangent to y^(2)=ax makes an angle 45^(@) with x-axis . Then its point of contact is

    A
    (a/2,a/4)
    B
    (-a/2,a/4)
    C
    (a/4,a/2)
    D
    (-a/4,a/2)

    • Similar Questions

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    Find the equations of the tangents to the ellipse 2x^2+y^2=8 which make an angle 45^@ with the major axis.

    Find the equation of the tangents to the circle x^(2)+y^(2)-4x-5y+3=0 which are inclined at 45^(@) with X axis.

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