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Equation of parabola whose vertex is (2,...

Equation of parabola whose vertex is (2, 5) and focus (2, 2) is

A

`(x-2)^(2)` = 12 (y-5)

B

`(x-2)^(2)` = - 12 (y-5)

C

`(x-2)^(2)` = 12 (y-2)

D

`(x-2)^(2) `= - 12 (y-2)

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • The equation of the parabola whose vertex is at (0,0) and focus is the point of intersection of x+y=2,2x-y=4 is

    A
    `y^(2)=2x`
    B
    `y^(2)=4x`
    C
    `y^(2)=8x`
    D
    `x^(2)=8y`
  • The equation of the directrix of the parabola whose vertex (3,2) and focus (2,-1) is

    A
    x+3y-19=0
    B
    y-2y-9=0
    C
    2x+6y-24=0
    D
    x-3y-19=0
  • If the equation of the directrix of the parabola whose vertex (3,2) and focus (2,-1) is ax+by+c=0 then the ascending order of a,b,c, is

    A
    a,b,c
    B
    b,c,a
    C
    c,a,b
    D
    b,a,c
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