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In the given figure, BOC is a diameter o...

In the given figure, `BOC` is a diameter of a circle and `AB =AC` . Then , `/_ ABC = ?`

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
Since an angle in a semicircle is a right angle `/_ BAC = 90^(@)`
`:. /_BAC + /_ ACB = 90^(@)`
Now, `AB= AC implies /_ABC = /_ ACB = 45^(@)`
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