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If w=alpha+ibeta where Beta 0 and z ne ...

If `w=alpha+ibeta` where `Beta 0 ` and `z ne 1` satisfies the condition that `((w- bar wz)/(1-z))` is purely real then the set of values of z is

A

{z : |z| = 1}

B

`{z ":" bar(z) = z}`

C

`{z ":"|z| ne 1}`

D

`{z ":"|z| = 1, z ne 1}`

Text Solution

Verified by Experts

The correct Answer is:
D
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