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2n boys are randomly divided into two su...

`2n` boys are randomly divided into two subgroups containint `n` boys each. The probability that eh two tallest boys are in different groups is `n//(2n-1)` b. `(n-1)//(2n-1)` c. `(n-1)//4n^2` d. none of these

A

`n/(2n-1)`

B

`1/2`

C

`(2n)/(2n+1)`

D

`(n^2+1)/(n^2+n)`

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