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Let A and B be two events of random expe...

Let A and B be two events of random experiment such that P(A') = 0.3, P(B) = 0.4 and P( A`nn` B' ) = 0.5, then P(A `uu`B) + P(B|A `uu`B') = ____

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To solve the problem step by step, we will use the given probabilities and apply the relevant formulas from probability theory. ### Step 1: Find P(A) We know that: \[ P(A') = 0.3 \] Using the complement rule: \[ P(A) = 1 - P(A') = 1 - 0.3 = 0.7 \] **Hint:** Remember that the probability of an event and its complement always sum to 1. ### Step 2: Identify Given Probabilities We have: - \( P(A) = 0.7 \) - \( P(B) = 0.4 \) - \( P(A' \cap B') = 0.5 \) ### Step 3: Find P(A ∩ B) We can use the relationship: \[ P(A) = P(A \cap B) + P(A \cap B') \] We know that: \[ P(A \cap B') = P(A') - P(A' \cap B) \] Since \( P(A' \cap B) = P(B) - P(A \cap B) \), we can rewrite it as: \[ P(A \cap B') = P(A) - P(A \cap B) \] From the information given: \[ P(A' \cap B') = 0.5 \] This means: \[ P(A \cup B) = 1 - P(A' \cap B') = 1 - 0.5 = 0.5 \] ### Step 4: Use the Union Formula Using the formula for the union of two events: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] Substituting the known values: \[ 0.5 = 0.7 + 0.4 - P(A \cap B) \] This simplifies to: \[ P(A \cap B) = 0.7 + 0.4 - 0.5 = 0.6 \] ### Step 5: Find P(A ∩ B) Now we can find \( P(A \cap B) \): \[ P(A \cap B) = P(A) + P(B) - P(A \cup B) \] Substituting the values: \[ P(A \cap B) = 0.7 + 0.4 - 0.5 = 0.6 \] ### Step 6: Find P(A ∪ B) We already have: \[ P(A \cup B) = 0.5 \] ### Step 7: Find P(B | A ∪ B') Using the conditional probability formula: \[ P(B | A \cup B') = \frac{P(B \cap (A \cup B'))}{P(A \cup B')} \] We know: \[ P(A \cup B') = 1 - P(A' \cap B) = 1 - 0.5 = 0.5 \] Now we need to find \( P(B \cap (A \cup B')) \): \[ P(B \cap (A \cup B')) = P(B) - P(B \cap A) = 0.4 - 0.2 = 0.2 \] ### Step 8: Calculate P(B | A ∪ B') Substituting into the conditional probability formula: \[ P(B | A \cup B') = \frac{0.2}{0.5} = 0.4 \] ### Step 9: Find the Final Result Now we can find: \[ P(A \cup B) + P(B | A \cup B') = 0.5 + 0.4 = 0.9 \] ### Final Answer The final answer is: \[ P(A \cup B) + P(B | A \cup B') = 0.9 \] ---
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MCGROW HILL PUBLICATION-PROBABILITY-Exercises (Numerical Answer)
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  2. A speaks 3 out of 5 times. He throws an unbiased die and reports it is...

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  3. An urn contains 5 blue and an unknown number x of red balls.Two balls ...

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  4. If P(AcapB)=7/10 and P(B)=17/20,then P(A/B) equals to

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  5. If P(A nnB)=1/2 and P(A' nn B')=1/3, P(A)=2p and P(B)=p , then the val...

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  6. Suppose A and B are two events such that P(A|B)=0.6, P(B|A)=0.3 , P(A)...

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  7. A problem is given to three students whose chances of solving it are ¼...

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  8. Suppose A and B are two events such that P(A)=1/4, P(B)=1/3 and P(AnnB...

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  9. Let A and B be two events, the probability that at least one of them o...

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  10. The probability that A speaks truth is 5/6, while this probability for...

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  12. Let S={{:[(a,b),(c,d)]:a,b,c,d in {0,1}:}} A matrix A is picked up at ...

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  13. Three boxes B1, B2 and B3, have the following composition of white an...

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  14. Let A,B and C be three events such that P(A)=0.50, P(B)=0.40, P(A nn...

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  15. E and F be two independent events such that P(E) lt P(F). The probabil...

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  16. Let A and B be two events such that P(A) = 1/3, P(B) = 1/4 and P( A nn...

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  17. Three numbers are chosen from the set {1, 2, 3, ..., 40} at random wit...

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  18. A random variable X has the following probability distribution: ...

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  19. If P(B)=3/4, P(AnnBnnbarC)=1/3 and P(barAnnBbarC)=1/3 then P(BnnC)=

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  20. A pair of fair dice is rolled together till a sum of 7 or 11 is obtain...

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