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Let A and B be two events of random expe...

Let A and B be two events of random experiment such that P(A') = 0.3, P(B) = 0.4 and P( A`nn` B' ) = 0.5, then P(A `uu`B) + P(B|A `uu`B') = ____

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To solve the problem step by step, we will use the given probabilities and apply the relevant formulas from probability theory. ### Step 1: Find P(A) We know that: \[ P(A') = 0.3 \] Using the complement rule: \[ P(A) = 1 - P(A') = 1 - 0.3 = 0.7 \] **Hint:** Remember that the probability of an event and its complement always sum to 1. ### Step 2: Identify Given Probabilities We have: - \( P(A) = 0.7 \) - \( P(B) = 0.4 \) - \( P(A' \cap B') = 0.5 \) ### Step 3: Find P(A ∩ B) We can use the relationship: \[ P(A) = P(A \cap B) + P(A \cap B') \] We know that: \[ P(A \cap B') = P(A') - P(A' \cap B) \] Since \( P(A' \cap B) = P(B) - P(A \cap B) \), we can rewrite it as: \[ P(A \cap B') = P(A) - P(A \cap B) \] From the information given: \[ P(A' \cap B') = 0.5 \] This means: \[ P(A \cup B) = 1 - P(A' \cap B') = 1 - 0.5 = 0.5 \] ### Step 4: Use the Union Formula Using the formula for the union of two events: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] Substituting the known values: \[ 0.5 = 0.7 + 0.4 - P(A \cap B) \] This simplifies to: \[ P(A \cap B) = 0.7 + 0.4 - 0.5 = 0.6 \] ### Step 5: Find P(A ∩ B) Now we can find \( P(A \cap B) \): \[ P(A \cap B) = P(A) + P(B) - P(A \cup B) \] Substituting the values: \[ P(A \cap B) = 0.7 + 0.4 - 0.5 = 0.6 \] ### Step 6: Find P(A ∪ B) We already have: \[ P(A \cup B) = 0.5 \] ### Step 7: Find P(B | A ∪ B') Using the conditional probability formula: \[ P(B | A \cup B') = \frac{P(B \cap (A \cup B'))}{P(A \cup B')} \] We know: \[ P(A \cup B') = 1 - P(A' \cap B) = 1 - 0.5 = 0.5 \] Now we need to find \( P(B \cap (A \cup B')) \): \[ P(B \cap (A \cup B')) = P(B) - P(B \cap A) = 0.4 - 0.2 = 0.2 \] ### Step 8: Calculate P(B | A ∪ B') Substituting into the conditional probability formula: \[ P(B | A \cup B') = \frac{0.2}{0.5} = 0.4 \] ### Step 9: Find the Final Result Now we can find: \[ P(A \cup B) + P(B | A \cup B') = 0.5 + 0.4 = 0.9 \] ### Final Answer The final answer is: \[ P(A \cup B) + P(B | A \cup B') = 0.9 \] ---
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Knowledge Check

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    D
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