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{:(HOOC-CH(2)-underset(NH(2))underset("|...

`{:(HOOC-CH_(2)-underset(NH_(2))underset("| ")("C ")H-COOH,underset((-COOH))(pK_(a_(1))),underset((-NH_(2)))(pK_(a_(2))),underset(("Acid or base of "-R))(pK_(a_(3)))),(" Aspartic acid"," 2.1"," 9.8"," 3.9"),(HOOC-underset(NH_(2))underset("| ")("C ")H-(CH_(2))_(4)-NH_(2),underset((-COOH))(pK_(a_(1))),underset((-NH_(2)))(pK_(a_(2))),underset(("Acid or base of "-R))(pK_(a_(3)))),(" Lysine"," 2.2"," 9.0"," 10.5"),(HOOC-underset(NH_(2))underset("| ")("C ")H-CH-OH,,,),(" Threonine"," 2.6"," 10.4",),(HOOC-underset(NH_(2))underset("| ")("C ")H-CH_(2)CH_(2)CONH_(2),,,),(" Glutamine"," 2.2"," 9.1",):}`
The aqueous solution of lysine is neutral at

A

pH = 7

B

pH = 9.8

C

`2.2`

D

`5.6`

Text Solution

Verified by Experts

The correct Answer is:
B
Neutral Form Exist under more basic condition
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