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For the reaction N(2)+3H(2)to2NH(3) , th...

For the reaction `N_(2)+3H_(2)to2NH_(3)` , the rate `(d[NH_(3)])/(dt)=2xx10^(-4)Ms^(-1)`. Therfore the rate `-(d[N_(2)])/(dt)` is given

A

`10^(-4)M"sec"^(-1)`

B

`10^(4)M"sec^(-1)`

C

`10^(-2)M"sec"^(-1)`

D

`4xx10^(-4)M"sec"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(r_(N_(2)))/1=(r_(H_(2)))/3=(r_(NH_(3)))/2,r_(N_(2))=(2xx10^(-4))/2=10^(-4)`
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Consider the following reaction: N_(2)(g) + 3H_(2)(g) to 2 NH_(3)(g) the rate of this reaction in terms of N_(2) at T K is =(-d[N_(2)])/(dt)= 0.02 mol L^(-1)s^(-1) . What is the value of (-d[N_(2)])/(dt) (in units of mol L^(-1)s^(-1) ) at the same temeprature.

Knowledge Check

  • For the reaction , N_(2)+3H_(2) to 2NH_(3), "if" (d[NH_(3)])/(dt)=2xx10^(-4)"mol"L^(-1)s^(-1), the value of (-d[H_(2)])/(dt) would be

    A
    `1xx10^(-4)"mol"L^(-1)s^(-1)`
    B
    `3xx10^(-4)"mol"L^(-1)s^(-1)`
    C
    `4xx10^(-4)"mol"L^(-1)s^(-1)`
    D
    `6xx10^(-4)"mol"L^(-1)s^(-1)`

  • For the reaction 4NH_(3)+5O_(2)to4NO+6H_(2)O , the rate of reaction with respect to NH_(3) is 2xx10^(-3)"Ms"^(-1) . Then the rate of the reaction with respect to oxygen is __ "Ms"^(-1)

    A
    `2xx10^(-3)`
    B
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    C
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    D
    `3xx10^(-3)`

  • The rate of reaction for N_(2)+3H_(2)to2NH_(3) may be represented as

    A
    `r=-(d[N_(2)])/(dt)=-1/3(d[H_(2)])/(dt)=+1/2(d[NH_(3)])/(dt)`
    B
    `r=-(d[N_(2)])/(dt)=1/3(d[H_(2)])/(dt)=+1/2(d[NH_(3)])/(dt)`
    C
    `r=-(d[N_(2)])/(dt)=-3(d[H_(2)])/(dt)=+1/2(d[NH_(3)])/(dt)`
    D
    `r=-(d[N_(2)])/(dt)=-1/3(d[H_(2)])/(dt)=+2(d[NH_(3)])/(dt)`

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