The energy of activation for a reaction ...

The energy of activation for a reaction is 100 kJ/mol at `57^(@)C`. Presence of catalyst lower activation energy by 25%. The rate of reaction is increased by `10^(x)` the value of x is

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The correct Answer is:

`(r_(2))/(r_(1))=(K_(2))/(K_(1))=(A.e^(-Ea_(2)//Rt))/(A.e^(-Ea_(1)//RT)),10^(x)=e^((-epsilona_(2)+epsilona_(2))/(RT))`
`2.303log_(10)10^(x)=(epsilon_(a_(1))-epsilon_(a_(2)))/(RT),2.303xx x=((100-75)xx10^(3))/(8.314xx330),x=(25xx1000)/(8.314xx330xx2.303)=3.95~=4`

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The use of a catalyst in chemical reaction…activation energy of the reaction

Increases

Decreases

Do not affect

Increases slightly

The activation energy of a reaction can be determined by

chaning the concentration of reactants

evaluating rate constnat at standard temperature

evaluateing rate constants at two different temperatures

by doubling conc. Of reactants

A: A catalyst increases the rate of a reaction. R: In presence of a catalyst, the activation energy of the reaction increases.

Both A and B are true and R is the correct explanation of A

Both A and R are true and R is not the correct explanation of A

A is true but R is false

A is false but R is true