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If the Planck's constant h = 6.6 xx 10^(...

If the Planck's constant `h = 6.6 xx 10^(-34) Js`, the de-Broglie wave length of a particle having momentum of `3.3 xx 10^(-24) kg.ms^(-1)` will be

A

`2 xx 10^(-10)m`

B

`1 xx 10^(-15) m`

C

`10^(-5)m`

D

`4 xx 10^(-10)m`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If the Planck's constant h = 6.6 xx 10^(-34) Js , the de-Broglie's wave length of a particle having momentum of 3.3 xx 10^(-24)kg.ms^(-1) will be

    A
    `2xx10^(-10)m`
    B
    `1xx10^(-15)m`
    C
    `10^(-5)m`
    D
    `4xx10^(-10)m`

  • The value of Plank's constant is 6.62618xx 10^(-34)Js . The number of significant figures in it is:

    A
    Six
    B
    Five
    C
    Three
    D
    Thirty four

  • The De-Broglie wavelength associated with a particle of mass 1 mg moving with a velocity of 10ms^(-1) is

    A
    `6.63xx10^(-29)m`
    B
    `6.63xx10^(-31)m`
    C
    `6.63xx10^(-34)m`
    D
    `6.63xx10^(-22)m`

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    A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813 xx 10^(-4) . Calculate the particle’s mass and identify the particle.

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