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Identify the order of the reaction from ...

Identify the order of the reaction from the rate constant `K= 2.3 xx 10^(-6) L " mol"^(-1)s^(-1)`

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order = 2, Or second order, Or 2nd order.
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Knowledge Check

  • The half life of the first order reaction having rate constant k= 1 cdot 7 xx 10^(-5) s^(-1) is

    A
    `12 cdot 1` h
    B
    `9 cdot 7` h
    C
    `11 cdot 3`h
    D
    `1 cdot 8`h

  • For the reaction of H_2 the rate constant is 2cdot5xx10^(-4) dm^3 mol^(-1) s^(-1) at 327^@ C and 1cdot0 dm^3 mol^(-1) s^(-1) at 527^@ C. The activation energy for the reaction, in kJ mol^(-1) is: (R=8cdot314 JK^(-1) mol^(-1))

    A
    150
    B
    72
    C
    59
    D
    166

  • The rate of a first order reaction has been found to be 2.45xx10^(-6) "mol L"^(-1) s^(-1) at concentration C_(1) . The value of C_(1) is (rate constant = 3.5xx10^(-5) ) :

    A
    7.0 mol `L^(-1)`
    B
    0.7 mol `L^(-1)`
    C
    0.07 mol `L^(-1)`
    D
    2.1 mol `L^(-1)`

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    For a reaction , the activation energy (E_a) = zero and the rate constant (k) = 3 cdot 2 xx 10^6 s^(-1) at 300 k. What will be the rate constant at 310 k?

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