Alumiunium chloride exists as dimer, `Al_(2)Cl_(6)` in solid state as well as in solution of non - polar solvents such as `C_(6)H_(6)`. When dissolved in water it gives :

Options

A. `Al_(2)O_(3)+6HCl`
B. `[Al(H_(2)O)_(6)]+3C^(-)`
C. `[Al(OH)_(6)]^(3-)+3HCl`
D. `Al^(3+)+3Cl^(-)`

Answer

C

Explanation

`AlCl_(3)+6H_(2)O rarr [Al(OH)_(2)]^(+3)+3HCl+3H^(+)`