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Compound A(C(6)H(13)NO) liberates hydrog...

Compound `A(C_(6)H_(13)NO)` liberates hydrogen on reaction with metallic sodium. A on reaction with `NaNO_(2)` and HCl was found to give three products `B(C_(6)H_(10)O),C(C_(6)H_(10)O)` and `D(C_(6)H_(12)O_(2))` a vicinal. Both B & C react with 2,4 – DNP to give coloured product. C reduces Fehling's solution, but not B. B on reduction with HI & Red P gave cyclohexane while C gave methylcyclophentane. D on reduction with HI & Red P also gave cyclohexane.
Study the reaction give above carefully and answer the following questions.
Compound 'B' is

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A


Compound C having aldehydic group so fehling solution reduces
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Knowledge Check

  • Compound A(C_(6)H_(13)O) liberates hydrogen on reaction with metallic sodium. A on reaction with NaNO_(2) and HCl was found to give three products B(C_(6)H_(10)O),C(C_(6)H_(10)O) and D(C_(6)H_(12)O_(2)) a vicinal. Both C & D react with 2,4 – DNP to give coloured product. C reduces Fehling's solution, but not B. B on reduction with HI & Red P gave cyclohexane while C gave methylcyclophentane. Don reduction with HI & Red P also gave cyclohexane. Study the reaction give above carefully and answer the following questions. Compound 'C' is

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  • Compound A(C_(6)H_(13)O) liberates hydrogen on reaction with metallic sodium. A on reaction with NaNO_(2) and HCl was found to give three products B(C_(6)H_(10)O),C(C_(6)H_(10)O) and D(C_(6)H_(12)O_(2)) a vicinal. Both C & D react with 2,4 – DNP to give coloured product. C reduces Fehling's solution, but not B. B on reduction with HI & Red P gave cyclohexane while C gave methylcyclophentane. Don reduction with HI & Red P also gave cyclohexane. Study the reaction give above carefully and answer the following questions. The structure of Compound 'A' is

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    combination
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    decomposition
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    displacement
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    double displacement
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