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The resistance of 0.5 N solution of an e...

The resistance of 0.5 N solution of an electrolyte in a conductivity cell was found to be 45 ohms. If the electrodes in the cell are 2.2 cm apart and have an area of `3.8 cm^2` then the equivalent conductance (in `Scm^2 eq^(-1)` ) of a solution is

A

25.73

B

15.75

C

30.75

D

35.75

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A
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Knowledge Check

  • The resistance of 0.01N solution of an electrolyte AB at 328K is 100 ohm. The specific conductance of solution is ( cell constant =1 cm^(-1) )

    A
    100 ohm
    B
    `10^(-2)ohm^(-1)`
    C
    `10^(-2) ohm^(-1).cm^(-1)`
    D
    `10^(2)ohm.cm`

  • The resistnce of 0.1 N solution of a salt is found to be 2.5xx10^(3) ohms. The equivalent conductance of the solution is ( cell constant =1.15cm^(-1) )

    A
    4.6
    B
    5.6
    C
    6.6
    D
    7.6

  • The distance between two electrodes of a cell is 2.5 cm and area of each electrode is 5 cm2 the cell constant (in "cm"-^(1) ) is

    A
    2
    B
    `12.5`
    C
    `7.5`
    D
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