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If alpha is a non real root of x^6=1 the...

If `alpha` is a non real root of `x^6=1` then `(alpha^5+alpha^3+alpha+1)/(alpha^2+1)=`

A

`alpha^2`

B

`-alpha^2`

C

`alpha`

D

0

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • If alpha is non real root of x^(6)=1 , then (alpha^(5)+alpha^(3)+alpha+1)/(alpha^(2)+1) is equal to

    A
    `alpha^(2)`
    B
    0
    C
    `-alpha^(2)`
    D
    `alpha`

  • If alpha is non -real root of x^7 =1 , then alpha(1+ alpha) (1+ alpha^2 + alpha^4) =

    A
    2
    B
    -1
    C
    1
    D
    -2

  • If alpha is a non-real root of x^(7) = 1 then alpha (1 + alpha)(1 + alpha^(2) + alpha^(4))=

    A
    1
    B
    2
    C
    `-1`
    D
    `-2`

    • Similar Questions

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    If alpha is a root of z^2 - z + 1 =0 then (alpha^(2014) +(1)/(alpha^(2014)))+ (alpha^(2015) (1)/(alpha^(2015)))^(2)+(alpha^(2016)+(1)/(alpha^(2016)))^3 + (alpha^(2017) + (1)/(alpha^(2017)))^4 + (alpha^(2018) + (1)/alpha^(2018))^5=

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