Home
Class 11
PHYSICS
A student measures the thickness of a hu...

A student measures the thickness of a human hair by looking at it through a microscope of magnification 100. He makes 20 observations and finds that the average width of the hair in the field of view of the microscope is 3.5 mm. The thickness of hair is

A

0.035 mm

B

0.04 mm

C

0.35 mm

D

0.40 mm

Text Solution

Verified by Experts

The correct Answer is:
A

0.035 mm
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • PHYSICAL WORLD AND MEASUREMENT

    MTG GUIDE|Exercise AIPMT / NEET MCQ|14 Videos
  • PHYSICAL WORLD AND MEASUREMENT

    MTG GUIDE|Exercise NEET CAFE TOPICWISE PRACTICE QUESTIONS (DIMENSIONAL ANALYSIS AND ITS APPLICATIONS)|38 Videos
  • OSCILLATIONS AND WAVES

    MTG GUIDE|Exercise AIPMT / NEET MCQs|43 Videos
  • PROPERTIES OF BULK MATTER

    MTG GUIDE|Exercise AIPMT/NEET (MCQs)|40 Videos

Similar Questions

Explore conceptually related problems

A student measures the thickness of a human hair by looking at it through a microscope of magnification 100. He makes 20 observations and findsd that the average width of the hair in the field of view of the microscope is 3.5mm. What is his estimate on the thickness of hair?

A boy measures the thickness of a human hair by looking at it through a microscope of magnification 100x. After 25 observations, the boy finds that the average width of the hair in the field of view of the microscope is 3.8 mm. What is the estimate on the thickness of hair?

Knowledge Check

  • A mark on a table top is seen by a student through a microscope at a distance of 30 cm from the microscope. Seeing along same vertical path he puts a slab in between microscope and table top at any position. He finds that he is to move the microscope by 5 cm, away from the salb to see the focussed image of the same mark. if refractive index of glass glass slab is 1.5. The thickness of glass slab introduced is

    A
    15 cm
    B
    5cm
    C
    30 cm
    D
    20 cm
  • The alternate discs of iron and carbon, having same area of cross-section are cemented together to make a cylinder whose temperature coefficient of resistivity is zero. The change in temperature in two alternate discs is same. The ratio of their thickness and ratio of heat produced in them is found out. The resistivity of iron and carbon at 20^@C" are "1 xx 10^(-7) and 3 xx 10^(-5)Omegam and their temperature coefficient of resistance are 5 xx 10^(-3)""^(@)C and -7.5 xx 10^(-4)""^(@)C, respectively, Thermal expansion is neglected. Here, triangleR_1 +triangleR_2= 0 (where triangleR_1, and triangleR_2 , are the increase in resistances of iron and carbon, respectively, with the rise in temperature) because combined temperature coefficient of resistivity is given as zero. A copper wire is stretched to make it 1% longer. The percentage change in its resistance is Electrical resistance of certain materials, known as super conductors changes abruptly from a non zero value to zero as their temperture is lowered below a critical temperature T_c(0) An interesting property of superconductors is that their critical temperature becomes smaller than T_c(0) if they are placed in a magnetic field, that is, the critical temperature T_c(B) is a function of the magnetic field strength B. The dependence of T_c(P) on magnetic field is shown in the below figure.

    A
    0.002
    B
    0.01
    C
    0.015
    D
    0.025
  • A student uses a metre scale, measuring upto 1 mm, to measure the length and breadth of a rectangular plate. He finds that length = 5.7 cm and breadth = 3.4 cm. What is the percentage error in the area of the plate ?

    A
    `3.5%`
    B
    `4.7%`
    C
    `5.3%`
    D
    `6.2%`
  • Similar Questions

    Explore conceptually related problems

    A glass plate 4 mm thick is viewed from the above through a microscope. The microscope must be lowered 2.58 mm as the operator shifts from viewing the top surface to viewing the bottom surface through the glass. What is the index of refraction of the glass ?

    When viewed normally through the flat surface the apparent thickness of a plano-covex lens appears to be 2mm . If the radius of curvature of the spherical surface is 10cm then find thickness of the lens when viewed from the curved surface. Refractive index of the glass is 1.5 .

    The focal length of the objective of a microscope is int_(0)=3mm and of the eyepiece int_(e)=5cm. An object the magnification of the microscope of 3.1 mm from the objective.Find the magnification of the microscope for a normal eye, if the final image is produced at a distance 25 cm from the eye or eyepiece .Also final the separation between the lenses of microscope 180 13.46 cm

    In a YDSE experiment, the distance between the slits & the screen is 100 cm . For a certain distance between the slits, an interference pattern is observed on the screen with the fringe width 0.25 mm . When the distance between the slits is increased by Deltad=1.2 mm, the fringe width decreased to n=2//3 of the original value. In the final position, a thin glass plate of refractive index 1.5 is kept in front of one of the slits & the shift of central maximum is observed to be 20 fringe width. Find the thickness of the plate & wavelength of the incident light.

    This interference film is used to measure the thickness of slides, paper, etc. The arrangement is as shown in fig. For the sake of clarity, the two strips are shown thick. Consider the wedge formed in between strips 1 and 2. If the interference pattern because of the two waves reflected from wedge surface is observed, then from the observed data we can compute thickness of paper, refractive index of the medium filled in wedge, number of bonds formed, etc. Considre the strips to be thick as compared to wavelength of ligth and light is incident normally. Neglect the effect due to reflection from top surface of strip 1 and bottom surface of strip 2. Take L = 5 cm and lambda_(air) = 40 nm . Consider an air wedge formed by two glass plates. having refractive index 1.5 by placing a piece of paper of thickness 20 mm. Determine the number of dark bands formed.